DCT

Let

$\displaystyle {\bf z}= {\rm DCT}({\bf x}).$

Then, the Jacobian of the DCT transformation is 1. Therefore,

$\displaystyle \log J = 0.$

No module_dct or module_dct_synth is defined because both operations are trivial and the J-function is just 1.



Baggenstoss 2017-05-19